What is the derivative of y=e^{3x}+10e^{2x} ?

The derivative of y=e^{3x}+10e^{2x} is e^{3x}*3+20e^{2x}

What is the first derivative of y=e^{3x}+10e^{2x} ?

The first derivative of y=e^{3x}+10e^{2x} is e^{3x}*3+20e^{2x}

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derivative of

y = e^{3 x} + 10 e^{2 x}

e^{3 x} \cdot 3 + 20 e^{2 x}

Solution steps

\frac{d}{d x} (e^{3 x} + 10 e^{2 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{3 x}) + \frac{d}{d x} (10 e^{2 x})

\frac{d}{d x} (e^{3 x}) = e^{3 x} \cdot 3

\frac{d}{d x} (10 e^{2 x}) = 20 e^{2 x}

= e^{3 x} \cdot 3 + 20 e^{2 x}

What is the derivative of y=e^{3x}+10e^{2x} ?
The derivative of y=e^{3x}+10e^{2x} is e^{3x}*3+20e^{2x}
What is the first derivative of y=e^{3x}+10e^{2x} ?
The first derivative of y=e^{3x}+10e^{2x} is e^{3x}*3+20e^{2x}