(y^2-2xy+6x)dx-(x^2-2xy+2)dy=0

Lösung

(y^{2} - 2 x y + 6 x) d x - (x^{2} - 2 x y + 2) d y = 0

y = \frac{2 + x ^{2} + ( - 2 - x ^{2} ) ^{2} - 4 x ( 3 x ^{2} - c _{1} )}{2 x}, y = \frac{2 + x ^{2} - ( - 2 - x ^{2} ) ^{2} - 4 x ( 3 x ^{2} - c _{1} )}{2 x}

Schritte zur Lösung

(y^{2} - 2 x y + 6 x) d x - (x^{2} - 2 x y + 2) d y = 0

Solve exact ODE:

y = \frac{2 + x ^{2} + ( - 2 - x ^{2} ) ^{2} - 4 x ( 3 x ^{2} - c _{1} )}{2 x}, y = \frac{2 + x ^{2} - ( - 2 - x ^{2} ) ^{2} - 4 x ( 3 x ^{2} - c _{1} )}{2 x}

y = \frac{2 + x ^{2} + ( - 2 - x ^{2} ) ^{2} - 4 x ( 3 x ^{2} - c _{1} )}{2 x}, y = \frac{2 + x ^{2} - ( - 2 - x ^{2} ) ^{2} - 4 x ( 3 x ^{2} - c _{1} )}{2 x}

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