e^xcos(y)dx+(1+e^x)sin(y)dy=0

Lösung

e^{x} cos (y) d x + (1 + e^{x}) sin (y) d y = 0

y = arccos (e^{- c_{1}} + e^{x - c_{1}}) + 2 πn, y = - arccos (e^{- c_{1}} + e^{x - c_{1}}) + 2 πn

Schritte zur Lösung

e^{x} cos (y) d x + (1 + e^{x}) sin (y) d y = 0

Solve separable ODE:

y = arccos (e^{- c_{1}} + e^{x - c_{1}}) + 2 πn, y = - arccos (e^{- c_{1}} + e^{x - c_{1}}) + 2 πn

y = arccos (e^{- c_{1}} + e^{x - c_{1}}) + 2 πn, y = - arccos (e^{- c_{1}} + e^{x - c_{1}}) + 2 πn

y^{^{'}} = 6 (x y)^{2}

(x y^{2} - x) d x + (2 x^{2} y + 8 y) d y = 0

y^{^{'}} = e^{- y} - 1

y^{^{'}} + y = 1, - H (t - 2) y (0) = 2

\frac{d x}{d y} = \frac{5 y}{6 x}