dy+(x^2y-x^2)dx=0

Lösung

d y + (x^{2} y - x^{2}) d x = 0

y = e^{- \frac{x ^{3}}{3} + c_{1}} + 1

Schritte zur Lösung

d y + (x^{2} y - x^{2}) d x = 0

Solve separable ODE:

y = e^{- \frac{x ^{3}}{3} + c_{1}} + 1

y = e^{- \frac{x ^{3}}{3} + c_{1}} + 1

\frac{d y}{d x} = \frac{y}{x ^{2} + 1}

e^{2 x} y^{^{'}} = y - y e^{3 x}

y^{^{'}} = 6 y - 15

\frac{d y}{d x} x = y^{4}

\frac{d x}{d t} = t x + 4 x + 3 t + 12