y^'+1/2 (x-2)y^2=0

Lösung

y^{^{'}} + \frac{1}{2} (x - 2) y^{2} = 0

y = - \frac{4}{- x ^{2} + 4 x + c _{1}}

Schritte zur Lösung

y^{'} (x) + \frac{1}{2} (x - 2) y^{2} = 0

Solve separable ODE:

y = - \frac{4}{- x ^{2} + 4 x + c _{1}}

y = - \frac{4}{- x ^{2} + 4 x + c _{1}}

x^{2} y^{^{'}} = 1 + y

y^{^{'}} = \frac{11 cos ( 11 x )}{3 + 2 y}, y (0) = - 1

\frac{d y}{d x} = (2 x) (y)

y^{^{'}} = \frac{1}{2} y^{3}

y^{^{'}} \cdot tan (x) - y = - 2