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Popular Calculus >

y^'=-ysin(2x)

Solution

y^{^{'}} = - y sin (2 x)

Solution

y = e^{\frac{1}{2} c o s (2 x) + c_{1}}

Solution steps

y^{'} (x) = - y sin (2 x)

Solve separable ODE:

y = e^{\frac{1}{2} c o s (2 x) + c_{1}}

y = e^{\frac{1}{2} c o s (2 x) + c_{1}}

Graph

Popular Examples

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integral of sin^{1/2}(x)

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Frequently Asked Questions (FAQ)

What is the solution for y^'=-ysin(2x) ?
The solution for y^'=-ysin(2x) is y=e^{1/2 cos(2x)+c_{1}}