What is the tangent of 110x-16x^2 ?

The tangent of 110x-16x^2 is y=(110-32a_{0})x+16a_{0}^2

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tangent of 110x-16x^2

tangent of

110 x - 16 x^{2}

y = (110 - 32 a_{0}) x + 16 a_{0}^{2}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 110 a_{0} - 16 a_{0}^{2})

Find the slope of

y = 110 x - 16 x^{2} : \frac{d y}{d x} = 110 - 32 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 110 - 32 a_{0}

Find the line with slope m=

110 - 32 a_{0}

and passing through

(a_{0}, 110 a_{0} - 16 a_{0}^{2}) : y = (110 - 32 a_{0}) x + 16 a_{0}^{2}

y = (110 - 32 a_{0}) x + 16 a_{0}^{2}

What is the tangent of 110x-16x^2 ?
The tangent of 110x-16x^2 is y=(110-32a_{0})x+16a_{0}^2