y^2dy=(2x+1)/(2y)dx

Lösung

y^{2} d y = \frac{2 x + 1}{2 y} d x

y = 4 2 x^{2} + 2 x + c_{1}, y = - 4 2 x^{2} + 2 x + c_{1}

Schritte zur Lösung

y^{2} d y = \frac{2 x + 1}{2 y} d x

Solve separable ODE:

y = 4 2 x^{2} + 2 x + c_{1}, y = - 4 2 x^{2} + 2 x + c_{1}

y = 4 2 x^{2} + 2 x + c_{1}, y = - 4 2 x^{2} + 2 x + c_{1}

sin (x) cos (x) y^{^{'}} - sin (y) cos (x) = 0

y^{^{'}} = \frac{1}{2} (k - y)

\frac{d y}{d x} = 6 e^{2 x - y}, y (0) = 0

5 x y d x - ln^{8} (y) d y = 0

y^{^{'}} = \frac{1}{3} y