y^'+n^2y-y=a

Lösung

y^{^{'}} + n^{2} y - y = a

y = \frac{e ^{- n^{2} t + t - c_{1} n^{2} + c_{1}}}{- n ^{2} + 1} - \frac{a}{- n ^{2} + 1}

Schritte zur Lösung

y^{'} (t) + n^{2} y - y = a

Solve separable ODE:

y = \frac{e ^{- n^{2} t + t - c_{1} n^{2} + c_{1}}}{- n ^{2} + 1} - \frac{a}{- n ^{2} + 1}

y = \frac{e ^{- n^{2} t + t - c_{1} n^{2} + c_{1}}}{- n ^{2} + 1} - \frac{a}{- n ^{2} + 1}

\frac{d y}{d t} = - 0.4 y + 28

(x - 2) y^{^{'}} - y + 1 = 0

a y^{^{'}} = - b y^{2} - c, y (0) = 10

(u - 1) d x + (x + ux) d u = 0

2 t (\frac{d y}{d t}) = 6 y