derivative of 4x^3+2y^5=6

解

\frac{d}{d x} (4 x^{3} + 2 y^{5}) = 6

y = 5 3 x + c_{1} - 2 x^{3}

解答ステップ

\frac{d}{d x} (4 x^{3} + 2 y^{5}) = 6

f^{^{'}} (x) = g (x)

であれば

f (x) = \int g (x) d x

4 x^{3} + 2 y^{5} = \int 6 d x

\int 6 d x = 6 x + c_{1}

4 x^{3} + 2 y^{5} = 6 x + c_{1}

分離する

y : y = 5 3 x + \frac{c _{1}}{2} - 2 x^{3}

y = 5 3 x + \frac{c _{1}}{2} - 2 x^{3}

簡素化

y = 5 3 x + c_{1} - 2 x^{3}