What is the tangent of f(x)=3x^3+4x^2,(-1,1) ?

The tangent of f(x)=3x^3+4x^2,(-1,1) is y=x+2

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tangent of f(x)=3x^3+4x^2,(-1,1)

tangent of

f (x) = 3 x^{3} + 4 x^{2}, (- 1, 1)

y = x + 2

Solution steps

Find the slope of

f (x) = 3 x^{3} + 4 x^{2} : \frac{df ( x )}{d x} = 9 x^{2} + 8 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 1

Find the line with slope m=

1

and passing through

(- 1, 1) : y = x + 2

y = x + 2

What is the tangent of f(x)=3x^3+4x^2,(-1,1) ?
The tangent of f(x)=3x^3+4x^2,(-1,1) is y=x+2