de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Rechnen >

y^'=(2sin(2x)cos(2x))y^2,y(0)=2

Lösung

y^{^{'}} = (2 sin (2 x) cos (2 x)) y^{2}, y (0) = 2

Lösung

y = \frac{4}{cos ( 4 x ) + 1}

Schritte zur Lösung

y^{'} (x) = (2 sin (2 x) cos (2 x)) y^{2}

Solve separable ODE:

y = \frac{4}{cos ( 4 x ) + 1}

y = \frac{4}{cos ( 4 x ) + 1}

Graph

Beliebte Beispiele

(dy)/(dt)y=cos(9t-13)

\frac{d y}{d t} y = cos (9 t - 13)

(dy)/(dx)+x^2y=x^2,y=2,x=0

\frac{d y}{d x} + x^{2} y = x^{2}, y = 2, x = 0

\H(x)(x)^2x^2dx=2x^3d\H(x)

H (x) (x)^{2} x^{2} d x = 2 x^{3} d H (x)

\frac{d y}{d t} = 1 - 3 y

y^'=(-15x^2+2)(4y+7)

y^{^{'}} = (- 15 x^{2} + 2) (4 y + 7)