x^'-5x=0

Lösung

x^{^{'}} - 5 x = 0

x = e^{5 t + c_{1}}

Schritte zur Lösung

x^{'} (t) - 5 x = 0

Solve separable ODE:

x = e^{5 t + c_{1}}

x = e^{5 t + c_{1}}

2 x (1 + y^{2}) d x - y (1 - 2 x^{2}) d y = 0

y^{^{'}} = y (x - 1)

\frac{d y}{d x} = - \frac{( 2 x - 1 )}{( 3 y + 7 )}

2 x^{2} y + 3 x y^{^{'}} - (2 x^{2} - 1) y = 0

x^{2} y^{2} + 3 x y^{^{'}} = 0