y^'=e^{9x-9y}

Lösung

y^{^{'}} = e^{9 x - 9 y}

y = \frac{ln ( e ^{9 x} + c _{1} )}{9}

Schritte zur Lösung

y^{'} (x) = e^{9 x - 9 y}

Solve separable ODE:

y = \frac{ln ( e ^{9 x} + c _{1} )}{9}

y = \frac{ln ( e ^{9 x} + c _{1} )}{9}

y^{^{'}} = \frac{e ^{y}}{cos ^{2} ( t )}

\frac{d y}{d x} = a y + b

\frac{1}{x} d x = \frac{1}{y} d y

x y^{2} y^{^{'}} = ln (x)

V^{^{'}} - V^{2} = 5