f^'(x)=-2*f(x)

Lösung

f^{^{'}} (x) = - 2 \cdot f (x)

f (x) = e^{- 2 x + c_{1}}

Schritte zur Lösung

f^{'} (x) = - 2 \cdot f (x)

Solve separable ODE:

f (x) = e^{- 2 x + c_{1}}

f (x) = e^{- 2 x + c_{1}}

\frac{d y}{d x} = 7 y - 1

(y^{2} sec (2 x) tan (2 x)) d x + y (sec (2 x) + 2) d y = 0

\frac{d S}{d t} + \frac{7 S}{2460} = 0.02

\frac{1}{2} y y^{^{'}} = t^{3}

y^{^{'}} + 0.5 y = 5