xy^'=y+xe^{y/x}

Lösung

x y^{^{'}} = y + x e^{\frac{y}{x}}

y = - x ln (- ln (x) - c_{1})

Schritte zur Lösung

x y^{'} (x) = y + x e^{\frac{y}{x}}

Solve using substitution:

y = - x ln (- ln (x) - c_{1})

y = - x ln (- ln (x) - c_{1})

\int_{- 4}^{2} - x^{2} - 2 x + 8 d x

t an g e n t y = sin (7 x) + sin^{2} (7 x), (0, 0)

\int_{0}^{1} ∣ 2 x - 1 ∣ d x

\int_{0}^{2 π} cos (3 t) e^{- 2 t} d t

y^{^{''}} - 2 y^{^{'}} + 82 y = 0