What is the integral of 1/(x*sqrt(x-1)) ?

The integral of 1/(x*sqrt(x-1)) is 2arctan(sqrt(x-1))+C

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integral of 1/(x*sqrt(x-1))

\int \frac{1}{x \cdot x - 1} d x

2 arctan (x - 1) + C

Solution steps

\int \frac{1}{x x - 1} d x

Apply u-substitution

= \int \frac{2}{u ^{2} + 1} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int \frac{1}{u ^{2} + 1} d u

Use the common integral:

\int \frac{1}{u ^{2} + 1} d u = arctan (u)

= 2 arctan (u)

Substitute back

u = x - 1

= 2 arctan (x - 1)

Add a constant to the solution

= 2 arctan (x - 1) + C

\frac{\partial}{\partial x} (\frac{x + 4}{y + 4})

\int \frac{1}{2 - cos ( x )} d x

\frac{\partial}{\partial x} (2 x + 2 y)

\frac{\partial}{\partial x} (9 x + y + 7 x y)

f^{^{'}} (x) = 1 - 2 x

What is the integral of 1/(x*sqrt(x-1)) ?
The integral of 1/(x*sqrt(x-1)) is 2arctan(sqrt(x-1))+C