y^{''}+9y=sin(x)-2

Lösung

y^{^{''}} + 9 y = sin (x) - 2

y = c_{1} cos (3 x) + c_{2} sin (3 x) + \frac{1}{8} sin (x) - \frac{2}{9}

Schritte zur Lösung

y^{''} (x) + 9 y = sin (x) - 2

Solve linear ODE:

y = c_{1} cos (3 x) + c_{2} sin (3 x) + \frac{1}{8} sin (x) - \frac{2}{9}

y = c_{1} cos (3 x) + c_{2} sin (3 x) + \frac{1}{8} sin (x) - \frac{2}{9}

y^{^{'''}} - y^{^{'}} = tan (x)

y^{^{''}} + 4 y^{^{'}} + 8 y = 12 e^{- 2 x} sec (2 x)

y^{^{''}} - 4 y = 20

y^{^{''}} + y = sinh (2 x)

y^{^{''}} + y^{^{'}} + 9.25 = 0