y^{'''}-y^{''}=6

Lösung

y^{^{'''}} - y^{^{''}} = 6

y = c_{1} e^{t} + c_{2} + c_{3} t - 3 t^{2}

Schritte zur Lösung

y^{'''} (t) - y^{''} (t) = 6

Solve linear ODE:

y = c_{1} e^{t} + c_{2} + c_{3} t - 3 t^{2}

y = c_{1} e^{t} + c_{2} + c_{3} t - 3 t^{2}

y^{^{''}} + 2 y^{^{'}} - 3 y = t, y (0) = 2, y^{^{'}} (0) = 1

y^{^{''}} + 4 y = 3 sin (x) + 3 cos (x)

y^{^{''}} - 2 y^{^{'}} = 1

y^{^{''}} - 2 y^{^{'}} = 4

y^{^{''}} + 4 y^{^{'}} + 3 y = e^{3 x}