y^{''}-9y=1

Lösung

y^{^{''}} - 9 y = 1

y = c_{1} e^{3 t} + c_{2} e^{- 3 t} - \frac{1}{9}

Schritte zur Lösung

y^{''} (t) - 9 y = 1

Solve linear ODE:

y = c_{1} e^{3 t} + c_{2} e^{- 3 t} - \frac{1}{9}

y = c_{1} e^{3 t} + c_{2} e^{- 3 t} - \frac{1}{9}

y^{^{''}} - 3 y^{^{'}} - 4 y = t^{2}, y (0) = 1, y^{^{'}} (0) = 4

y^{^{''}} + 9 y = sin (3 t), y (0) = 1, y^{^{'}} (0) = 1

y^{^{'''}} - 7 y^{^{'}} - 6 y = 26 e^{- 2 x} cos (x)

y^{^{''}} - 4 y = 20 t - 20 e^{- 2 t}, y (0) = 0, y^{^{'}} (0) = 12

y^{^{''}} - 2 y^{^{'}} - 2 y = 5 x - 1 + e^{4 x}