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Beliebt Rechnen >

y^{''}+4y^'=-32(x+2),y(0)=0,y^'(0)=-10

Lösung

y^{^{''}} + 4 y^{^{'}} = - 32 (x + 2), y (0) = 0, y^{^{'}} (0) = - 10

Lösung

y = 1 - e^{- 4 x} - 4 x^{2} - 14 x

Schritte zur Lösung

y^{''} (x) + 4 y^{'} (x) = - 32 (x + 2)

Solve linear ODE:

y = 1 - e^{- 4 x} - 4 x^{2} - 14 x

y = 1 - e^{- 4 x} - 4 x^{2} - 14 x

Graph

Beliebte Beispiele

3y^{''}-4y^'-5y=(x^2+1)e^{-x}

3 y^{^{''}} - 4 y^{^{'}} - 5 y = (x^{2} + 1) e^{- x}

2y^{''}+y^'+1=2e^2x

2 y^{^{''}} + y^{^{'}} + 1 = 2 e^{2} x

y^{'''}-2y^'=2,y^{''}(0)=-1

y^{^{'''}} - 2 y^{^{'}} = 2, y^{^{''}} (0) = - 1

y^{''}+4y=sin(x)*sin(2x)

y^{^{''}} + 4 y = sin (x) \cdot sin (2 x)

y^{''}+y^'=cos(x),y(0)=0,y^'(0)=1

y^{^{''}} + y^{^{'}} = cos (x), y (0) = 0, y^{^{'}} (0) = 1