y^{''}+y^'=(2t)

Lösung

y^{^{''}} + y^{^{'}} = (2 t)

y = c_{1} + c_{2} e^{- t} + t^{2} - 2 t

Schritte zur Lösung

y^{''} (t) + y^{'} (t) = (2 t)

Solve linear ODE:

y = c_{1} + c_{2} e^{- t} + t^{2} - 2 t

y = c_{1} + c_{2} e^{- t} + t^{2} - 2 t

y^{^{''}} + 3 y + 2 = 0, y (2) = - 1, y^{^{'}} (0) = 0

y^{^{''}} - 2 y^{^{'}} + 2 y = e - t, y (0) = 0, y^{^{'}} (0) = 1

y^{^{''}} - 2 y - 3 y = - 3 x e^{- x}

y^{^{''}} + 6 y^{^{'}} + 8 y = t H (t - 3)

\frac{1}{2} y^{^{''}} + 2 y = 4 tan (2 t) - \frac{1}{3} e^{2 t}