What is the integral of-(1000)/(x^2) ?

The integral of-(1000)/(x^2) is (1000)/x+C

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integral of-(1000)/(x^2)

\int - \frac{1000}{x ^{2}} d x

\frac{1000}{x} + C

Solution steps

\int - \frac{1000}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 1000 \cdot \int \frac{1}{x ^{2}} d x

Apply the Power Rule

= - 1000 (- \frac{1}{x})

Simplify

- 1000 (- \frac{1}{x}) : \frac{1000}{x}

= \frac{1000}{x}

Add a constant to the solution

= \frac{1000}{x} + C

\int_{0}^{3} \frac{1}{3 - x} d x

\int cos (x) e^{- 3 x} d x

d er i v a t i v e 2 sin (3 x)

\frac{\partial}{\partial x} (\frac{( 4 x - 4 y )}{4 x + 4 y})

\frac{\partial}{\partial x} (tan (8 + 2 x^{2} y^{4} z^{2}))

What is the integral of-(1000)/(x^2) ?
The integral of-(1000)/(x^2) is (1000)/x+C