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Beliebt Rechnen >

2y^{''}+20y^'+51y=0,y(0)=2,y^'(0)=0

Lösung

2 y^{^{''}} + 20 y^{^{'}} + 51 y = 0, y (0) = 2, y^{^{'}} (0) = 0

Lösung

y = e^{- 5 t} (2 cos (\frac{t}{2}) + 102 sin (\frac{t}{2}))

Schritte zur Lösung

2 y^{''} (t) + 20 y^{'} (t) + 51 y = 0

Solve linear ODE:

y = e^{- 5 t} (2 cos (\frac{t}{2}) + 102 sin (\frac{t}{2}))

y = e^{- 5 t} (2 cos (\frac{t}{2}) + 102 sin (\frac{t}{2}))

Graph

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