y^{''}-by=0

Lösung

y^{^{''}} - b y = 0

y = c_{1} e^{b t} + c_{2} e^{- b t}

Schritte zur Lösung

y^{''} (t) - b y = 0

Solve linear ODE:

y = c_{1} e^{b t} + c_{2} e^{- b t}

y = c_{1} e^{b t} + c_{2} e^{- b t}

49 y^{^{''}} - 168 y^{^{'}} + 144 y = 0

(D^{3} - 8) y = 0

4 \frac{d ^{2} y}{d x ^{2}} + 36 y = 0

2 y - 3 y^{^{''}} = 0

y^{^{''}} + 4 y^{^{'}} - 7 y = 0