1x^{''}+6x^'-1x=0

Lösung

1 x^{^{''}} + 6 x^{^{'}} - 1 x = 0

x = c_{1} e^{(- 3 + 10) t} + c_{2} e^{(- 3 - 10) t}

Schritte zur Lösung

1 x^{''} (t) + 6 x^{'} (t) - 1 x = 0

Solve linear ODE:

x = c_{1} e^{(- 3 + 10) t} + c_{2} e^{(- 3 - 10) t}

x = c_{1} e^{(- 3 + 10) t} + c_{2} e^{(- 3 - 10) t}

6 y^{^{''''}} + 77 y^{^{''}} + 25 y = 0

y^{^{''}} - 3 y^{^{'}} + 2 y = 0, y (0) = 2, y^{^{'}} (0) = - 6

y^{^{''}} - 7 y^{^{'}} + 12 y = 0, y (0) = 1

y^{^{''}} + 15 y^{^{'}} + 44 y = 0, y (0) = 1, y^{^{'}} (0) = 0

y^{^{''}} + 12 y^{^{'}} + 36 y = 0, y (- 1) = 2, y^{^{'}} (- 1) = 5