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Beliebt Rechnen >

y^{''}-2y^'+2y=0,y(0)=2,y^'(0)=0

Lösung

y^{^{''}} - 2 y^{^{'}} + 2 y = 0, y (0) = 2, y^{^{'}} (0) = 0

Lösung

y = e^{t} (2 cos (t) - 2 sin (t))

Schritte zur Lösung

y^{''} (t) - 2 y^{'} (t) + 2 y = 0

Solve linear ODE:

y = e^{t} (2 cos (t) - 2 sin (t))

y = e^{t} (2 cos (t) - 2 sin (t))

Graph

Beliebte Beispiele

x^{''}-9x^'-14x=0

x^{^{''}} - 9 x^{^{'}} - 14 x = 0

(d^2y)/(dt^2)+(dy)/(dt)=0

\frac{d ^{2} y}{d t ^{2}} + \frac{d y}{d t} = 0

y^{''}+10y^'+25y=0,y(-1)=2,y^'(-1)=3

y^{^{''}} + 10 y^{^{'}} + 25 y = 0, y (- 1) = 2, y^{^{'}} (- 1) = 3

linear 2y^{''}+16y^'+82y=0

l in e a r 2 y^{^{''}} + 16 y^{^{'}} + 82 y = 0

y^{''''}-y^{'''}+y^{''}=0

y^{^{''''}} - y^{^{'''}} + y^{^{''}} = 0