What is the derivative of (x^6/(12)+1/(8x^4)) ?

The derivative of (x^6/(12)+1/(8x^4)) is (x^5)/2-1/(2x^5)

What is the first derivative of (x^6/(12)+1/(8x^4)) ?

The first derivative of (x^6/(12)+1/(8x^4)) is (x^5)/2-1/(2x^5)

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\frac{d}{d x} (\frac{x ^{6}}{12} + \frac{1}{8 x ^{4}})

\frac{x ^{5}}{2} - \frac{1}{2 x ^{5}}

Solution steps

\frac{d}{d x} (\frac{x ^{6}}{12} + \frac{1}{8 x ^{4}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{6}}{12}) + \frac{d}{d x} (\frac{1}{8 x ^{4}})

\frac{d}{d x} (\frac{x ^{6}}{12}) = \frac{x ^{5}}{2}

\frac{d}{d x} (\frac{1}{8 x ^{4}}) = - \frac{1}{2 x ^{5}}

= \frac{x ^{5}}{2} - \frac{1}{2 x ^{5}}

What is the derivative of (x^6/(12)+1/(8x^4)) ?
The derivative of (x^6/(12)+1/(8x^4)) is (x^5)/2-1/(2x^5)
What is the first derivative of (x^6/(12)+1/(8x^4)) ?
The first derivative of (x^6/(12)+1/(8x^4)) is (x^5)/2-1/(2x^5)