What is the integral from 1 to e of ln(17x) ?

The integral from 1 to e of ln(17x) is eln(17e)-e-ln(17)+1

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integral from 1 to e of ln(17x)

\int_{1}^{e} ln (17 x) d x

e ln (17 e) - e - ln (17) + 1

Decimal

5.86825 \dots

Solution steps

\int_{1}^{e} ln (17 x) d x

Apply Integration By Parts

= [x ln (17 x) - \int 1 d x]_{1}^{e}

\int 1 d x = x

= [x ln (17 x) - x]_{1}^{e}

Compute the boundaries:

e ln (17 e) - e - ln (17) + 1

= e ln (17 e) - e - ln (17) + 1

What is the integral from 1 to e of ln(17x) ?
The integral from 1 to e of ln(17x) is eln(17e)-e-ln(17)+1