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Popular Calculus >

integral from-1 to 0 of x^3+1

Solution

\int_{- 1}^{0} x^{3} + 1 d x

Solution

\frac{3}{4}

+1

Decimal

0.75

Solution steps

\int_{- 1}^{0} x^{3} + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{0} x^{3} d x + \int_{- 1}^{0} 1 d x

\int_{- 1}^{0} x^{3} d x = - \frac{1}{4}

\int_{- 1}^{0} 1 d x = 1

= - \frac{1}{4} + 1

Simplify

- \frac{1}{4} + 1 : \frac{3}{4}

= \frac{3}{4}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from-1 to 0 of x^3+1 ?
The integral from-1 to 0 of x^3+1 is 3/4