What is the solution for y^'=(2x)/(y+x^2y) ?

The solution for y^'=(2x)/(y+x^2y) is y=sqrt(2ln(1+x^2)+c_{1)},y=-sqrt(2ln(1+x^2)+c_{1)}

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y^'=(2x)/(y+x^2y)

y^{^{'}} = \frac{2 x}{y + x ^{2} y}

y = 2 ln (1 + x^{2}) + c_{1}, y = - 2 ln (1 + x^{2}) + c_{1}

Solution steps

y^{'} (x) = \frac{2 x}{y + x ^{2} y}

Solve separable ODE:

y = 2 ln (1 + x^{2}) + c_{1}, y = - 2 ln (1 + x^{2}) + c_{1}

y = 2 ln (1 + x^{2}) + c_{1}, y = - 2 ln (1 + x^{2}) + c_{1}

What is the solution for y^'=(2x)/(y+x^2y) ?
The solution for y^'=(2x)/(y+x^2y) is y=sqrt(2ln(1+x^2)+c_{1)},y=-sqrt(2ln(1+x^2)+c_{1)}