What is the solution for y^'=((y+y^2))/(x^2) ?

The solution for y^'=((y+y^2))/(x^2) is y=(e^{c_{1}})/(e^{1/x)-e^{c_{1}}}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^'=((y+y^2))/(x^2)

y^{^{'}} = \frac{( y + y ^{2} )}{x ^{2}}

y = \frac{e ^{c_{1}}}{e ^{\frac{1}{x}} - e ^{c_{1}}}

Solution steps

y^{'} (x) = \frac{( y + y ^{2} )}{x ^{2}}

Solve separable ODE:

y = \frac{e ^{c_{1}}}{e ^{\frac{1}{x}} - e ^{c_{1}}}

y = \frac{e ^{c_{1}}}{e ^{\frac{1}{x}} - e ^{c_{1}}}

What is the solution for y^'=((y+y^2))/(x^2) ?
The solution for y^'=((y+y^2))/(x^2) is y=(e^{c_{1}})/(e^{1/x)-e^{c_{1}}}