What is the integral from-infinity to x of 1/(x^2) ?

The integral from-infinity to x of 1/(x^2) is -1/x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from-infinity to x of 1/(x^2)

\int_{- \infty}^{x} \frac{1}{x ^{2}} d x

- \frac{1}{x}

Solution steps

\int_{- \infty}^{x} \frac{1}{x ^{2}} d x

Compute the indefinite integral:

\int \frac{1}{x ^{2}} d x = - \frac{1}{x} + C

Compute the boundaries:

\int_{- \infty}^{x} \frac{1}{x ^{2}} d x = - \frac{1}{x} - 0

= - \frac{1}{x} - 0

Simplify

= - \frac{1}{x}

What is the integral from-infinity to x of 1/(x^2) ?
The integral from-infinity to x of 1/(x^2) is -1/x