What is (\partial)/(\partial x)(A+B(x^2+y^2)) ?

The answer to (\partial)/(\partial x)(A+B(x^2+y^2)) is 2Bx

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(\partial)/(\partial x)(A+B(x^2+y^2))

\frac{\partial}{\partial x} (A + B (x^{2} + y^{2}))

2 B x

Solution steps

\frac{\partial}{\partial x} (A + B (x^{2} + y^{2}))

Treat

A, B, y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (A) + \frac{\partial}{\partial x} (B (x^{2} + y^{2}))

\frac{\partial}{\partial x} (A) = 0

\frac{\partial}{\partial x} (B (x^{2} + y^{2})) = 2 B x

= 0 + 2 B x

Simplify

= 2 B x

What is (\partial)/(\partial x)(A+B(x^2+y^2)) ?
The answer to (\partial)/(\partial x)(A+B(x^2+y^2)) is 2Bx