What is the tangent of 2x^2-8x-7 ?

The tangent of 2x^2-8x-7 is y=(4a_{0}-8)x-2a_{0}^2-7

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tangent of 2x^2-8x-7

tangent of

2 x^{2} - 8 x - 7

y = (4 a_{0} - 8) x - 2 a_{0}^{2} - 7

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 2 a_{0}^{2} - 8 a_{0} - 7)

Find the slope of

y = 2 x^{2} - 8 x - 7 : \frac{d y}{d x} = 4 x - 8

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 4 a_{0} - 8

Find the line with slope m=

4 a_{0} - 8

and passing through

(a_{0}, 2 a_{0}^{2} - 8 a_{0} - 7) : y = (4 a_{0} - 8) x - 2 a_{0}^{2} - 7

y = (4 a_{0} - 8) x - 2 a_{0}^{2} - 7

What is the tangent of 2x^2-8x-7 ?
The tangent of 2x^2-8x-7 is y=(4a_{0}-8)x-2a_{0}^2-7