What is the derivative of f(x)=(x-3)/(x+4) ?

The derivative of f(x)=(x-3)/(x+4) is 7/((x+4)^2)

What is the first derivative of f(x)=(x-3)/(x+4) ?

The first derivative of f(x)=(x-3)/(x+4) is 7/((x+4)^2)

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derivative of

f (x) = \frac{x - 3}{x + 4}

\frac{7}{( x + 4 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x - 3}{x + 4})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x - 3 ) ( x + 4 ) - \frac{d}{d x} ( x + 4 ) ( x - 3 )}{( x + 4 ) ^{2}}

\frac{d}{d x} (x - 3) = 1

\frac{d}{d x} (x + 4) = 1

= \frac{1 \cdot ( x + 4 ) - 1 \cdot ( x - 3 )}{( x + 4 ) ^{2}}

Simplify

\frac{1 \cdot ( x + 4 ) - 1 \cdot ( x - 3 )}{( x + 4 ) ^{2}} : \frac{7}{( x + 4 ) ^{2}}

= \frac{7}{( x + 4 ) ^{2}}

What is the derivative of f(x)=(x-3)/(x+4) ?
The derivative of f(x)=(x-3)/(x+4) is 7/((x+4)^2)
What is the first derivative of f(x)=(x-3)/(x+4) ?
The first derivative of f(x)=(x-3)/(x+4) is 7/((x+4)^2)