What is the tangent of f(x)=sqrt(x),\at x= 1/9 ?

The tangent of f(x)=sqrt(x),\at x= 1/9 is y= 3/2 x+1/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

tangent of f(x)=sqrt(x),\at x= 1/9

tangent of

f (x) = x, at x = \frac{1}{9}

y = \frac{3}{2} x + \frac{1}{6}

Solution steps

Find the tangent point:

(\frac{1}{9}, \frac{1}{3})

Find the slope of

f (x) = x : \frac{df ( x )}{d x} = \frac{1}{2 x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{3}{2}

Find the line with slope m=

\frac{3}{2}

and passing through

(\frac{1}{9}, \frac{1}{3}) : y = \frac{3}{2} x + \frac{1}{6}

y = \frac{3}{2} x + \frac{1}{6}

What is the tangent of f(x)=sqrt(x),\at x= 1/9 ?
The tangent of f(x)=sqrt(x),\at x= 1/9 is y= 3/2 x+1/6