What is the derivative of ((2x-1)/(x^2)) ?

The derivative of ((2x-1)/(x^2)) is (2(-x+1))/(x^3)

What is the first derivative of ((2x-1)/(x^2)) ?

The first derivative of ((2x-1)/(x^2)) is (2(-x+1))/(x^3)

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\frac{d}{d x} (\frac{( 2 x - 1 )}{x ^{2}})

\frac{2 ( - x + 1 )}{x ^{3}}

Solution steps

\frac{d}{d x} (\frac{( 2 x - 1 )}{x ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 2 x - 1 ) x ^{2} - \frac{d}{d x} ( x ^{2} ) ( 2 x - 1 )}{( x ^{2} ) ^{2}}

\frac{d}{d x} (2 x - 1) = 2

\frac{d}{d x} (x^{2}) = 2 x

= \frac{2 x ^{2} - 2 x ( 2 x - 1 )}{( x ^{2} ) ^{2}}

Simplify

\frac{2 x ^{2} - 2 x ( 2 x - 1 )}{( x ^{2} ) ^{2}} : \frac{2 ( - x + 1 )}{x ^{3}}

= \frac{2 ( - x + 1 )}{x ^{3}}

What is the derivative of ((2x-1)/(x^2)) ?
The derivative of ((2x-1)/(x^2)) is (2(-x+1))/(x^3)
What is the first derivative of ((2x-1)/(x^2)) ?
The first derivative of ((2x-1)/(x^2)) is (2(-x+1))/(x^3)