What is the integral from 0 to 1 of 2^x ?

The integral from 0 to 1 of 2^x is 1/(ln(2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from 0 to 1 of 2^x

\int_{0}^{1} 2^{x} d x

\frac{1}{ln ( 2 )}

Decimal

1.44269 \dots

Solution steps

\int_{0}^{1} 2^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= [\frac{2 ^{x}}{ln ( 2 )}]_{0}^{1}

Compute the boundaries:

\frac{1}{ln ( 2 )}

= \frac{1}{ln ( 2 )}

What is the integral from 0 to 1 of 2^x ?
The integral from 0 to 1 of 2^x is 1/(ln(2))