derivative of ln(8-4x)

解答

\frac{d}{d x} (ln (8 - 4 x))

- \frac{1}{2 - x}

求解步骤

\frac{d}{d x} (ln (8 - 4 x))

使用连锁律:

\frac{1}{8 - 4 x} \frac{d}{d x} (8 - 4 x)

= \frac{1}{8 - 4 x} \frac{d}{d x} (8 - 4 x)

\frac{d}{d x} (8 - 4 x) = - 4

= \frac{1}{8 - 4 x} (- 4)

化简

\frac{1}{8 - 4 x} (- 4) : - \frac{1}{2 - x}

= - \frac{1}{2 - x}

d er i v a t i v e f (x) = 3

x \to 9 - lim (\frac{2}{x - 9})

\int tan^{4} (8 x) d x

d er i v a t i v e y = e^{2} + 2 x

\frac{d}{d x} (\frac{e ^{a x} - e ^{- a x}}{e ^{a x} + e ^{- a x}})