What is the derivative of (x-1/(x+3)) ?

The derivative of (x-1/(x+3)) is 4/((x+3)^2)

What is the first derivative of (x-1/(x+3)) ?

The first derivative of (x-1/(x+3)) is 4/((x+3)^2)

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\frac{d}{d x} (\frac{x - 1}{x + 3})

\frac{4}{( x + 3 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x - 1}{x + 3})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x - 1 ) ( x + 3 ) - \frac{d}{d x} ( x + 3 ) ( x - 1 )}{( x + 3 ) ^{2}}

\frac{d}{d x} (x - 1) = 1

\frac{d}{d x} (x + 3) = 1

= \frac{1 \cdot ( x + 3 ) - 1 \cdot ( x - 1 )}{( x + 3 ) ^{2}}

Simplify

\frac{1 \cdot ( x + 3 ) - 1 \cdot ( x - 1 )}{( x + 3 ) ^{2}} : \frac{4}{( x + 3 ) ^{2}}

= \frac{4}{( x + 3 ) ^{2}}

What is the derivative of (x-1/(x+3)) ?
The derivative of (x-1/(x+3)) is 4/((x+3)^2)
What is the first derivative of (x-1/(x+3)) ?
The first derivative of (x-1/(x+3)) is 4/((x+3)^2)