(dy}{dx}=\frac{-e^x)/8

Lösung

\frac{d y}{d x} = \frac{- e ^{x}}{8}

y = - \frac{1}{8} e^{x} + c_{1}

Schritte zur Lösung

\frac{d y}{d x} = \frac{- e ^{x}}{8}

Ersetze

\frac{d y}{d x}

mit

y^{'} (x)

y^{^{'}} (x) = \frac{- e ^{x}}{8}

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

y = \int \frac{- e ^{x}}{8} d x

\int \frac{- e ^{x}}{8} d x = - \frac{1}{8} e^{x} + c_{1}

y = - \frac{1}{8} e^{x} + c_{1}

\frac{\partial}{\partial y} (x y e^{z})

d er i v a t i v e cos (7 x)

x \to - 1 - lim ({2 x^{2} - 5 x})

\frac{d}{d x} (3 sec^{2} (π x - 1))

t an g e n t f (x) = \frac{x ^{2}}{x + 1}, at x = 2