What is area y=x^2-4x+3,x-y-1=0 ?

The answer to area y=x^2-4x+3,x-y-1=0 is 9/2

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area y=x^2-4x+3,x-y-1=0

area

y = x^{2} - 4 x + 3, x - y - 1 = 0

\frac{9}{2}

Decimal

4.5

Solution steps

Isolate

y

for

x - y - 1 = 0 : y = x - 1

Apply the area formula:

\int_{1}^{4} x^{2} - 4 x + 3 - (x - 1) d x

Solve

\int_{1}^{4} x^{2} - 4 x + 3 - (x - 1) d x : \frac{9}{2}

The area is:

= \frac{9}{2}