integral of (x^2-9)

Lösung

\int (x^{2} - 9) d x

\frac{x ^{3}}{3} - 9 x + C

Schritte zur Lösung

\int x^{2} - 9 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{2} d x - \int 9 d x

\int x^{2} d x = \frac{x ^{3}}{3}

\int 9 d x = 9 x

= \frac{x ^{3}}{3} - 9 x

Füge eine Konstante zur Lösung hinzu

= \frac{x ^{3}}{3} - 9 x + C

\int \frac{x ( x - 6 )}{( x - 3 ) ^{3}} d x

\int \frac{3}{9 - 4 x ^{2}} d x

y^{^{''}} - y^{^{'}} - 6 y = - 4 e^{2 t}, y (0) = 0, y^{^{'}} (0) = 0

d er i v a t i v e f (x) = \frac{2 - x ^{2}}{2 + x ^{2}}

d er i v a t i v e f (x)