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受欢迎的微积分 >

tangent sqrt(x)+sqrt(y)=sqrt(2)

解答

切线

x + y = 2

解答

y = (- \frac{2}{a _{0}} + 1) x + a_{0} \frac{2}{a _{0}} - 22 a_{0} + 2

求解步骤

计算在一般点

x = a_{0}

的切线

找到切点:

(a_{0}, 2 - 22 a_{0} + a_{0})

计算

x + y = 2

的斜率:

\frac{d y}{d x} = - \frac{2}{x} + 1

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{2}{a _{0}} + 1

找到斜率 m=

- \frac{2}{a _{0}} + 1

且穿过

(a_{0}, 2 - 22 a_{0} + a_{0})

的直线:

y = (- \frac{2}{a _{0}} + 1) x + a_{0} \frac{2}{a _{0}} - 22 a_{0} + 2

y = (- \frac{2}{a _{0}} + 1) x + a_{0} \frac{2}{a _{0}} - 22 a_{0} + 2

作图

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