What is the integral from 1 to 3 of 3/x-3/(x^2) ?

The integral from 1 to 3 of 3/x-3/(x^2) is 3ln(3)-2

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integral from 1 to 3 of 3/x-3/(x^2)

\int_{1}^{3} \frac{3}{x} - \frac{3}{x ^{2}} d x

3 ln (3) - 2

Decimal

1.29583 \dots

Solution steps

\int_{1}^{3} \frac{3}{x} - \frac{3}{x ^{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{3} \frac{3}{x} d x - \int_{1}^{3} \frac{3}{x ^{2}} d x

\int_{1}^{3} \frac{3}{x} d x = 3 ln (3)

\int_{1}^{3} \frac{3}{x ^{2}} d x = 2

= 3 ln (3) - 2

What is the integral from 1 to 3 of 3/x-3/(x^2) ?
The integral from 1 to 3 of 3/x-3/(x^2) is 3ln(3)-2