What is the solution for y^'=((x^2+y^2))/(xy) ?

The solution for y^'=((x^2+y^2))/(xy) is y=xsqrt(2ln(x)+c_{1)},y=-xsqrt(2ln(x)+c_{1)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^'=((x^2+y^2))/(xy)

y^{^{'}} = \frac{( x ^{2} + y ^{2} )}{x y}

y = x 2 ln (x) + c_{1}, y = - x 2 ln (x) + c_{1}

Solution steps

y^{'} (x) = \frac{( x ^{2} + y ^{2} )}{x y}

Solve Bernoulli ODE:

y = x 2 ln (x) + c_{1}, y = - x 2 ln (x) + c_{1}

y = x 2 ln (x) + c_{1}, y = - x 2 ln (x) + c_{1}

What is the solution for y^'=((x^2+y^2))/(xy) ?
The solution for y^'=((x^2+y^2))/(xy) is y=xsqrt(2ln(x)+c_{1)},y=-xsqrt(2ln(x)+c_{1)}