What is the derivative of (yx^2) ?

The derivative of (yx^2) is (dy)/(dx)x^2+2xy

What is the first derivative of (yx^2) ?

The first derivative of (yx^2) is (dy)/(dx)x^2+2xy

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

\frac{d}{d x} ((y) x^{2})

\frac{d y}{d x} x^{2} + 2 x y

Solution steps

\frac{d}{d x} ((y) x^{2})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = y, g = x^{2}

= \frac{d y}{d x} x^{2} + \frac{d}{d x} (x^{2}) y

\frac{d}{d x} (x^{2}) = 2 x

= \frac{d y}{d x} x^{2} + 2 x y

What is the derivative of (yx^2) ?
The derivative of (yx^2) is (dy)/(dx)x^2+2xy
What is the first derivative of (yx^2) ?
The first derivative of (yx^2) is (dy)/(dx)x^2+2xy