y^'-(4y)/t =5

Lösung

y^{^{'}} - \frac{4 y}{t} = 5

y = - \frac{5 t}{3} + c_{1} t^{4}

Schritte zur Lösung

y^{'} (t) - \frac{4 y}{t} = 5

Solve linear ODE:

y = - \frac{5 t}{3} + c_{1} t^{4}

y = - \frac{5 t}{3} + c_{1} t^{4}

d er i v a t i v e \frac{6 x ^{2} + 1}{x ^{2} + 9}

\frac{d}{d x} (\frac{- cos ( x )}{x})

\int \frac{5 x e ^{2 x}}{( 1 + 2 x ) ^{2}} d x

\int sin^{5} (3 x) cos^{3} (3 x) d x

\frac{d}{d x} (arctan (- 4 x))