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Beliebt Rechnen >

y^{''}+4y^'+6y=0,y(0)=-4,y^'(0)=-1

Lösung

y^{^{''}} + 4 y^{^{'}} + 6 y = 0, y (0) = - 4, y^{^{'}} (0) = - 1

Lösung

y = e^{- 2 t} (- 4 cos (2 t) - \frac{9}{2} sin (2 t))

Schritte zur Lösung

y^{''} (t) + 4 y^{'} (t) + 6 y = 0

Solve linear ODE:

y = e^{- 2 t} (- 4 cos (2 t) - \frac{9}{2} sin (2 t))

y = e^{- 2 t} (- 4 cos (2 t) - \frac{9}{2} sin (2 t))

Graph

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